What is the major product of the following re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of $4$-bromo-$1$-pentene with alcoholic $KOH$ is a dehydrohalogenation ($E2$ elimination) reaction. The removal of $HBr$ from $C-3$ a

Vedclass · Accepted Answer

$CH_2=CH-CH=CH-CH_3$

Vedclass · Answer

(C) The reaction of $4$-bromo-$1$-pentene with alcoholic $KOH$ is a dehydrohalogenation ($E2$ elimination) reaction. The removal of $HBr$ from $C-3$ and $C-4$ positions results in the formation of $1,3$-pentadiene $(CH_2=CH-CH=CH-CH_3)$,which is a conjugated diene and more stable than the isolated diene ($1,4$-pentadiene) formed by elimination from $C-4$ and $C-5$. Thus,$1,3$-pentadiene is the major product.

What is the major product of the following reaction?
$CH_2=CH-CH_2-CH(Br)-CH_3 + KOH \xrightarrow[\text{heat}]{\text{alcohol}} \dots$

Similar Questions

The isomeric deuterated bromide with molecular formula $C_4H_8DBr$ having two chiral carbon atoms is

The products $A$ and $B$ in the following reactions,respectively,are:
$A \xleftarrow{AgNO_2} CH_3-CH_2-CH_2-Br \xrightarrow{AgCN} B$

The compound having the longest $C-Cl$ bond is:

Which type of rate is observed in dehydrohalogenation ($\beta$-elimination) reaction of alkyl halide?

Which of the following is the most reactive towards $S_{N}1$ mechanism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the major product of the following reaction? $CH_2=CH-CH_2-CH(Br)-CH_3 + KOH \xrightarrow[\text{heat}]{\text{alcohol}} \dots$